A.1:3:5B.3:5:15C.1:1:2D.2:2:1答案:
设A1的示数为5A,则A2的示数为3A,A3的示数为1A,因三电阻并联,所以I1+I2+I3=5A,I2+I3=3A,I3=1A;
解得I2=2A,I1=2A;所以R1:R2:R3=UI1:UI2:UI3=12A:12A:11A=1:1:2.
故选C.来源:天天语录网
A.1:3:5B.3:5:15C.1:1:2D.2:2:1答案:
设A1的示数为5A,则A2的示数为3A,A3的示数为1A,因三电阻并联,所以I1+I2+I3=5A,I2+I3=3A,I3=1A;
解得I2=2A,I1=2A;所以R1:R2:R3=UI1:UI2:UI3=12A:12A:11A=1:1:2.
故选C.