(1)开关S1、S2都闭合时,电阻R1与R2串联,
∵I=UR,∴U=IR,UV1UV2=I(R1+R2)IR2=R1+R2R2=53,
R1R2=23,R2=32R1;(2)开关S1闭合,S2断开时,三个电阻串联,
∵I=UR,∴U=IR,UV1′UV2′=I′(R1+R2+R3)I′(R2+R3)=R1+R2+R3R2+R3=R1+32R1+R332R1+R3=32,
R3=12R1,全部通电时间内,电阻R1、R3产生的热量之比
Q1Q2=I′2R1tI′2R3t=R1R3=R112R1=21;故答案为:2:3;2:1.
来源:天天语录网